(x^2+5x+2)+(X^2+2x+7)=0

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Solution for (x^2+5x+2)+(X^2+2x+7)=0 equation: 



(x^2+5x+2)+(x^2+2x+7)=0

We get rid of parentheses

x^2+x^2+5x+2x+2+7=0

We add all the numbers together, and all the variables

2x^2+7x+9=0

a = 2; b = 7; c = +9;
Δ = b2-4ac
Δ = 72-4·2·9
Δ = -23
Delta is less than zero, so there is no solution for the equation

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